36x^2+36x-6=0

Solution for 36x^2+36x-6=0 equation:

36x^2+36x-6=0

a = 36; b = 36; c = -6;
Δ = b2-4ac
Δ = 362-4·36·(-6)
Δ = 2160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2160}=\sqrt{144*15}=\sqrt{144}*\sqrt{15}=12\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12\sqrt{15}}{2*36}=\frac{-36-12\sqrt{15}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12\sqrt{15}}{2*36}=\frac{-36+12\sqrt{15}}{72}
$